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ChemistryChemical EquilibriumProblems involving KpMedium2 minQB
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Pure N2O4(g) at 2 atm initial pressure is heated to 350 K in a closed vessel. At equilibrium, 25% of N2O4 is dissociated into NO2(g). The Kp for N2O4(g) ⇌ 2NO2(g) is

Options:

Answer:
C
Solution:

Start with 1 mol N2O4, α = 0.25: N2O4 = 0.75, NO2 = 0.50; total = 1.25 mol Total pressure = 2 × 1.25 = 2.5 atm

PN2O4 = (0.75/1.25) × 2.5 = 1.2 atm and PNO2 = (0.50/1.25) × 2.5 = 0.8 atm

Kp = (0.8)2/1.2 = 0.53 atm

This is option (c).

Stream:JEESubject:ChemistryTopic:Chemical EquilibriumSubtopic:Problems involving Kp
⏱ 2mℹ️ Source: QB

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