Chemistry - Chemical Equilibrium Question with Solution | TestHub

$2\mathrm{NO} + {\mathrm{O}}_2\to 2\mathrm{NO}$

$\begin{array}{ccc}2& 1& -\\ 2-2\mathrm{x}& 1-\mathrm{x}& 2\mathrm{x}\\ 1.2& 0.6& 0.8\end{array}$

Total number of moles=$2.6$

According to Dalton's law,

Partial pressure$=$$$Total pressure$\times$Mole fraction

Mole fraction$=\frac{\mathrm{Number} \mathrm{of} \mathrm{moles} \mathrm{of} \mathrm{one} \mathrm{component}}{\mathrm{Total} \mathrm{number} \mathrm{of} \mathrm{moles}}$

${\mathrm{K}}_{\mathrm{P}}=\frac{{{\mathrm{P}}^2}_{{\mathrm{NO}}_2}}{{{\mathrm{P}}^2}_{\mathrm{NO}}.{\mathrm{P}}_{{\mathrm{O}}_2}}$

     $=$$\frac{{\displaystyle {\left(\frac{0.8}{2.6}\times 1\right)}^2}}{{\left(\frac{1.2}{2.6}\times 1\right)}^2\left(\frac{0.6}{2.6}\times 1\right)}$=$=\frac{1.664}{0.864}=1.8824\simeq 2$