Chemistry - Chemical Equilibrium Question with Solution | TestHub

K at$298 \mathrm{K}$for the reaction
$\mathrm{A}+\mathrm{B}\mathrm{ }\rightleftharpoons \mathrm{C}+\mathrm{D}$is$100$.

Given: The initial concentration of all four species is$1 \mathrm{M}$.
$\begin{array}{cccccccc}& \mathrm{A}& +& \mathrm{B}& \rightleftharpoons & \mathrm{C}& +& \mathrm{D}\\ \mathrm{t}=0& 1& & 1& & 1& & 1\\ \mathrm{at} \mathrm{equilbrium}& 1-\mathrm{x}& & 1-\mathrm{x}& & 1+\mathrm{x}& & 1+\mathrm{x}\end{array}$

$\mathrm{K}=\frac{\left(1+\mathrm{x}\right)\mathrm{ }\left(1+\mathrm{x}\right)}{\left(1-\mathrm{x}\right)\mathrm{ }\left(1-\mathrm{x}\right)}=100$
$\Rightarrow$$\frac{\left(1+\mathrm{x}\right)}{1-\mathrm{x}}=10$
$\Rightarrow$$\mathrm{x}=\frac{9}{11}=0.818$
$\Rightarrow$$\left[\mathrm{D}\right]=1+\mathrm{x}=1+0.818=1.818$