In reaction A + 2 B ⇌ 2 C + D , initial concentration of B was 1.5 times of [ A ] , but at equilibrium the concentrations of A and B became equal. The equilibrium constant for the reaction is :

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Hence K C ​ = ( a − x ) ( 1.5 a − 2 x ) 2 ( 2 x ) 2 × x ​ Given, at equilibrium ∴ ∴ ​ ( a − x ) = ( 1.5 a − 2 x ) a = 2 x ​ On solving K C ​ = 4

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