Chemistry - Atomic Structure Question with Solution | TestHub

Ionisation energy$\text{13.6}\times {\mathrm{z}}^2=\text{54.4}$
$\therefore \text{Z}\text{=}\text{2}$
$\text{r}\text{=}\text{0}\text{.529}\frac{{\text{n}}^{\text{2}}}{\text{z}}\stackrel{\text{o}}{\text{A}}\text{=}\text{0}\text{.529}\text{×}\frac{{\text{2}}^{\text{2}}}{\text{2}}\text{=}\text{1}\text{.058}\stackrel{\text{o}}{\text{A}}$