Chemistry - Atomic Structure Question with Solution | TestHub

If an electron is present in ${\mathrm{S}}_3$ orbital then probability of finding electron at coordinates ( $\mathrm{x}=0$, $\mathrm{y}=2,\mathrm{z}=0$ ) is zero.

In case of multi-electronic species, energy, order is ${\mathrm{S}}_3<{\mathrm{S}}_1<{\mathrm{S}}_2$.

Orbital angular momentum of electron in ${\mathrm{S}}_1$ orbital is equal to zero.

For both ${\mathrm{S}}_3$ as well as ${\mathrm{S}}_1$ orbital radial, probability density will be maximum at nucleus.