Chemistry - Atomic Structure Question with Solution | TestHub

ChemistryAtomic StructureMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

The energy of an electron in the first orbit of $H^{} -$ atom is $- 13.6 e V$ . The possible energy values of the excited state for electrons in Bohr orbits of ${L i}^{2 +}$ ions is/are-

Options:

Answer:

Solution:

$E_{n} = - \frac{13.6 Z^{2}}{n^{2}}$ for ${L i}^{2 +}, E_{n} = - \frac{13.6 \times 9}{n^{2}}$

$= \frac{- 122.4}{n^{2}} e V$

If $n = 1, E_{n} = - 122.4 e V$

If $n = 2, E_{n} = - 30.6 e V$

If $n = 3, E_{n} = - 13.6 e V$

Stream:NTA_ABHYASSubject:ChemistryTopic:Atomic StructureSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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