Chemistry - Atomic Structure Question with Solution | TestHub

ChemistryAtomic StructureMiscellaneous/MixedEasy2 minPYQ_2020
ChemistryEasysingle choice

When photons of energy4.25 eVstrike the surface of a metal A, the ejected photoelectrons have maximum kinetic energy,TA(expressed in eV) and de Broglie wavelengthλA.The maximum kinetic energy of photoelectrons liberated from another metal B by photons of energy4.20 eV is TB=TA-1.50 eV.If the de Broglie wavelength of these photoelectrons isλB=2λA,then which is not correct?

Options:

Answer:
D
Solution:

λ= h mV
V A = h m λ A ; V B = h m λ B
V A V B = λ B λ A = 2 λ A λ A =2
T A T B = m V A 2 m V B 2 = V A V B 2 = 2 2 =4
AlsoTA-TB=1.50
So,TB=0.50
TA=0.50+1.50=2.00 eV
Also,4.25=hv0A+TA,
Sohv0A=4.25-2.00=2.25 eV
4.20=hv0B+TB, hv0B=4.20-0.50=3.70 eV

Stream:NTA_ABHYASSubject:ChemistryTopic:Atomic StructureSubtopic:Miscellaneous/Mixed
2mℹ️ Source: PYQ_2020

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