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Chemistry - Atomic Structure Question with Solution | TestHub

ChemistryAtomic StructureSchrödinger's EquationEasy2 minPYQ_2004

ChemistryEasysingle choice

For principle quantum number $n = 4$ , the total number of orbitals having $l = 3$ is

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Solution:

$: n = 4$ $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{10} 4 s^{2} 4 p^{6} 4 d^{10} 4 f^{14}$ $l = 3$ only for $f$ orbital. Thus the total number of orbitals for $l = 3$ is equal to 7 (because $f$ contains seven orbitals).

Stream:AIIMSSubject:ChemistryTopic:Atomic StructureSubtopic:Schrödinger's Equation

⏱ 2mℹ️ Source: PYQ_2004

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