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ChemistryAtomic StructureMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasynumerical

The wave number of first line of Balmer series of hydrogen is 1520 $m^{- 1}$ . The wave number of first Balmer line of $L i^{2 +}$ ion in $m^{- 1}$ is $x$ . Find the value of $\frac{x}{100}$ .

Answer:

136.80

Solution:

For a given line of hydrogen-like species, frequency, $\bar{v} \propto Z^{2}$

So $\frac{{\bar{v}}_{1}}{{\bar{v}}_{2}} = \frac{Z_{1}^{2}}{Z_{2}^{2}}$

or ${\bar{v}}_{2} = \frac{{\bar{v}}_{2} \times Z_{2}^{2}}{Z_{1}^{2}}$

$= \frac{1520 m^{- 1} \times (3)^{2}}{(1)^{2}}$

$= 13680 m^{- 1}$

Stream:NTA_ABHYASSubject:ChemistryTopic:Atomic StructureSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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