When a concentrated solution of sulphanilic acid and 1-naphthylamine is treated with nitrous acid ( 273 K) and acidified with acetic acid, the mass ( g) of 0.1 mole of product formed is :
(Given molar mass in $g mol^{- 1} H : 1, C : 12, N : 14$ , $O : 16, S : 32)$

Question

Question diagram: When a concentrated solution of sulphanilic acid and 1-napht

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Answer:

C

Solution:

0.1 mole of red-azo dye $($ Molar Mass $= 327 gm / mol)$ will have 32.7 gm mass. Nearly 33 gm.

TestHub · Accepted Answer

0.1 mole of red-azo dye ( Molar Mass = 327 gm / mol ) will have 32.7 gm mass. Nearly 33 gm.

Chemistry - AMINES Question with Solution | TestHub

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