A train of mass M is moving on a circle track of radius ' R ' with constant speed V . The length of the train is half of the perimeter of the track. The magnitude of linear momentum of the t

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A train of mass M is moving on a circle track of radius ' R ' with constant speed V . The length of the train is half of the perimeter of the track. The magnitude of linear momentum of the train will be :-

TestHub · Accepted Answer

d P = ( dm ) V ∴ d P = ( λ ) ( Rd θ ) V ; ∴ d P = ( λ Rd θ ) V ​ ∴ d P x ​ = [( λ R d θ ) ( V )] cos θ ​ P x ​ ​ = ∫ 0 P x ​ ​ ​ d P x ​ = λ R V ∫ − π /2 π /2 ​ cos θ d θ ​ ​ ∴ P x ​ = ( λ R V ) ( 2 ) = 2 λ R V ​ ​ = ( 2 R V ) ( π R M ​ ) = π 2 V M ​ Y components of the two elements cancel each other while x components are added

Physics - Circular Motion Question with Solution | TestHub

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