A fixed wedge ABC is in the shape of an equilateral triangle of side $ℓ$ . Initially, a chain of length $2 ℓ$ and mass m rests on the wedge inside of a tube as shown. The chain is pulled slightly, as a result it starts sliding out of the tube. Work done by gravity till the time, the chain leaves the wedge will be :-

Question

TestHub · Accepted Answer

Initially the chain lies ℓ on each side; COM height = 2 ℓ ​ sin 6 0 ∘ = 4 ℓ 3 ​ ​ . The chain leaves the wedge when its trailing end passes C: the whole 2 ℓ hangs vertically below C, so final COM height = − ℓ . W g ​ = m g Δ h COM ​ = m g ( 4 ℓ 3 ​ ​ + ℓ ) = 4 ( 3 ​ + 4 ) m g ℓ ​ . Answer: (D)

Physics - Center of Mass Question with Solution | TestHub

Options:

Doubts & Discussion