Two moles of an ideal gas at temperature T 0 = 300 K were cooled isochorically so that the pressure was reduced to half. Then, in an isobaric process, the gas expanded until its temperature returned

Question

Two moles of an ideal gas at temperature T 0 ​ = 300 K were cooled isochorically so that the pressure was reduced to half. Then, in an isobaric process, the gas expanded until its temperature returned to the initial value. Find the total amount of heat absorbed by the gas in the process.

TestHub · Accepted Answer

The initial and final temperatures are equal, so Δ U = 0 and the net heat equals the net work. Only the isobaric step does work. After the isochoric step T = 150 K. Q = W = n R Δ T = 2 × 8.314 × 150 = 2494 J.

Physics - Heat & Thermo Question with Solution | TestHub

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