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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoThermal ExpansionMedium2 minQB

PhysicsMediumnumerical

200 g of water at 0°C is in an insulated vessel connected to a vacuum pump. The maximum mass of water that can be frozen is found. $L_{v} = 2.52 \times 1 0^{6} J / kg$ and $L_{f} = 3.36 \times 1 0^{5} J / kg$ . Give the mass in g (two decimals).

Answer:

176.47

Solution:

Let x freeze: $x (3.36 \times 1 0^{5}) = (200 - x) (2.52 \times 1 0^{6}) . x = \frac{200 ( 25.2 )}{28.56} = 176.47 g$ .

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermal Expansion

⏱ 2mℹ️ Source: QB

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