A sensor obeys R = R 0 ( 1 + a C ) with R 0 = 100Ω , a = 0.00 4 ∘ C − 1 . Find Celsius temperature when R = 180Ω . Give one decimal.

180 = 100 ( 1 + 0.004 C ) , giving C = 0.004 0.8 = 200. 0 ∘ C . This uses a stated calibration law, not R proportional to Kelvin T.

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PhysicsHeat & ThermoThermal ExpansionMedium2 minQB

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A sensor obeys $R = R_{0} (1 + a C)$ with $R_{0} = 100Ω, a = 0.00 4^{\circ} C^{- 1}$ . Find Celsius temperature when $R =$ $180Ω$ . Give one decimal.

Answer:

200.00

Solution:

$180 = 100 (1 + 0.004 C)$ , giving $C = \frac{0.8}{0.004} = 200. 0^{\circ} C$ . This uses a stated calibration law, not R proportional to Kelvin T.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermal Expansion

⏱ 2mℹ️ Source: QB

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