Two cubic metres of dry air at NTP expand to 8 cubic metres adiabatically ( γ = 1.4 , 1 atm = 1.013 × 1 0 5 Pa). Find the work done in units of 1 0 5 J (two decimals).

P 2 = 1.013 × 1 0 5 × 4 − 1.4 = 14545 Pa. W = γ − 1 P 1 V 1 − P 2 V 2 = 0.4 2.026 × 1 0 5 − 116363 = 2.16 × 1 0 5 J.

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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoThermodynamics Laws & Specific Heats of GasesHard2 minQB

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Two cubic metres of dry air at NTP expand to 8 cubic metres adiabatically ( $γ = 1.4$ , 1 atm = $1.013 \times 1 0^{5}$ Pa). Find the work done in units of $1 0^{5}$ J (two decimals).

Answer:

2.16

Solution:

$P_{2} = 1.013 \times 1 0^{5} \times 4^{- 1.4} = 14545$ Pa. $W = \frac{P _{1} V _{1} - P _{2} V _{2}}{γ - 1} = \frac{2.026 \times 1 0 ^{5} - 116363}{0.4} = 2.16 \times 1 0^{5}$ J.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermodynamics Laws & Specific Heats of Gases

⏱ 2mℹ️ Source: QB

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