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PhysicsHeat & ThermoKTGMedium2 minQB

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Two moles of monoatomic gas are mixed with 1 mole of a diatomic gas. The $γ$ for the mixture is:

Answer:

Solution:

$C_{V} = \frac{2 \times \frac{3 R}{2} + 1 \times \frac{5 R}{2}}{3} = \frac{11 R}{6}; C_{P} = C_{V} + R = \frac{17 R}{6}$ .

$γ = \frac{C _{P}}{C _{V}} = \frac{17}{11} .$

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:KTG

⏱ 2mℹ️ Source: QB

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