If there is no heat loss, the heat released by the condensation of x gram of steam at 10 0 ∘ C into water at 10 0 ∘ C can be used to convert y gram of ice at 0 ∘ C into water at 10 0 ∘ C . Then the ra

Question

If there is no heat loss, the heat released by the condensation of x gram of steam at 10 0 ∘ C into water at 10 0 ∘ C can be used to convert y gram of ice at 0 ∘ C into water at 10 0 ∘ C . Then the ratio of y : x is nearly [Given L f ​ = 80 cal/gm and L v ​ = 540 cal/gm]

TestHub · Accepted Answer

Heat released by the steam: Q = x L v ​ Heat needed to melt the ice and warm the water to 10 0 ∘ C : Q = y L f ​ + 100 y S w ​ 540 x = 80 y + 100 y 540 x = 180 y x y ​ = 3

Physics - Heat & Thermo Question with Solution | TestHub

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