Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoThermal ExpansionMedium2 minQB

PhysicsMediumsingle choice

Scale X has ice/steam points 40°/120°; scale Y has -30°/130°. If X reads 50°, Y reads:

Answer:

Solution:

$\frac{50 - 40}{120 - 40} = \frac{Y + 30}{130 + 30}$ . Thus $Y + 30 = 20$ and $Y = - 1 0^{\circ}$ .

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermal Expansion

⏱ 2mℹ️ Source: QB

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