A gun fires a lead bullet of temperature 300 K into a wooden block. The bullet having melting temperature of 600 K penetrates into the block and melts down. If the total heat required for the process

Question

A gun fires a lead bullet of temperature 300 K into a wooden block. The bullet having melting temperature of 600 K penetrates into the block and melts down. If the total heat required for the process is 625 J , then the mass of the bullet is grams. (Latent heat of fusion of lead $= 2.5 \times 1 0^{4} JKg^{- 1}$ and specific heat capacity of lead $= 125 JKg^{- 1}$ $K^{- 1})$

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Answer:

A

Solution:

$625 = ms Δ T + mL 625 = m [125 \times 300 + 2.5 \times 1 0^{4}] 625 = m [37500 + 25000] 625 = m [62500] m = \frac{1}{100} kg M = 10 grams$

TestHub · Accepted Answer

​ 625 = ms Δ T + mL 625 = m [ 125 × 300 + 2.5 × 1 0 4 ] 625 = m [ 37500 + 25000 ] 625 = m [ 62500 ] m = 100 1 ​ kg M = 10 grams ​

Physics - Heat & Thermo Question with Solution | TestHub

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