The molar heat capacity in a process of a diatomic gas, if it does a work of 4 Q when a heat of Q is supplied to it, is:

Δ U = 4 3 Q = n 2 5 R Δ T , so n Δ T = 10 R 3 Q . C = n Δ T Q = 3 10 R . C.

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PhysicsHeat & ThermoThermodynamics Laws & Specific Heats of GasesMedium2 minQB

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The molar heat capacity in a process of a diatomic gas, if it does a work of $\frac{Q}{4}$ when a heat of $Q$ is supplied to it, is:

Answer:

Solution:

$Δ U = \frac{3 Q}{4} = n \frac{5}{2} R Δ T$ , so $n Δ T = \frac{3 Q}{10 R}$ . $C = \frac{Q}{n Δ T} = \frac{10}{3} R$ . C.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermodynamics Laws & Specific Heats of Gases

⏱ 2mℹ️ Source: QB

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