Two moles of an ideal gas at 300 K expand at constant pressure to three times the volume. Then the gas is cooled at constant volume to its initial temperature. Find the work done by the gas in joules

Question

Two moles of an ideal gas at 300 K expand at constant pressure to three times the volume. Then the gas is cooled at constant volume to its initial temperature. Find the work done by the gas in joules (nearest integer). What is Δ U for the whole process?

TestHub · Accepted Answer

Δ U = 0 (same start and end temperature). Only the isobaric step does work: T goes 300 → 900 K, so W = n R Δ T = 2 × 8.314 × 600 = 9977 J.

Physics - Heat & Thermo Question with Solution | TestHub

Doubts & Discussion