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PhysicsHeat & ThermoCalorimetryEasy2 minPYQ_2020
PhysicsEasysingle choice

A calorimeter of water equivalent20 gcontains180 gof water at25°C.m''' grams of steam at100°Cis mixed in it till the temperature of the mixture is31°C. The value ofm''is close to (Latent heat of water =540 cal g-1, specific heat of water=1 cal g-1°C-1)

Options:

Answer:
A
Solution:

20031-25=m×540+m169

1200=m609

m2

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:Calorimetry
2mℹ️ Source: PYQ_2020

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