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PhysicsNLMMedium2 minQB

PhysicsMediumsingle choice

What is the minimum value of applied force F so that both the block lifts up. Consider string to be ideal and pulley to be massless & frictionless

Answer:

Solution:

$cos θ = \frac{- 2 + 3}{2 + 3} = \frac{1}{26} sin θ = \frac{25}{26}$

Stream:JEESubject:PhysicsTopic:NLM

⏱ 2mℹ️ Source: QB

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