Physics - NLM Question with Solution | TestHub

$\mathrm{N}=50-20=30\mathrm{N}$ Limiting friction force $=\mu \mathrm{N}=12\mathrm{N}$ and applied force in horizontal direction is less than the limiting friction force, therefore the block will not slide. For equilibrium in horizontal direction, friction force must be equal to 10 N. From the top view, it is clear that $\theta =37^{\circ }$ i.e. $127^{\circ }$ from the x-axis that is the direction of the friction force. It is opposite to the applied force.

Contact force $\sqrt{{\mathrm{N}}^2+{\mathrm{f}}^2}=10\sqrt{10}\mathrm{N}$