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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoThermodynamicsMedium2 minQB

PhysicsMediumsingle choice

An ideal gas obeys a law $V^{2} P =$ constant. The gas is initially at temperature $T$ and have volume $V$ . As it expands to $2 V$ the temperature becomes

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Solution:

$P V^{2} =$ const $\Rightarrow T V =$ const (using $P V \propto T$ ) .

$T^{'} = \frac{T V}{2 V} = \frac{T}{2} .$

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:Thermodynamics

⏱ 2mℹ️ Source: QB

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