Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoSecond Law of ThermodynamicsHard2 minPYQ_2021

PhysicsHardsingle choice

The entropy of any system is given by,
$S = α^{2} β \ln [\frac{μ kR}{J β^{2}} + 3]$
where $α$ and $β$ are the constants. $μ, J, k$ and $R$ are number of moles, mechanical equivalent of heat, Boltzmann's constant and gas constant, respectively.
$[Take S = \frac{d Q}{T}]$
Choose the incorrect option from the following:

Options:

Answer:

Solution:

$S = α^{2} β ℓ n (\frac{μ k R}{J β^{2}} + 3)$
$S = \frac{Q}{T} = Joule k^{- 1}$
$[α^{2} β] = Joule k^{- 1}$
$P V = n R T [\frac{μ k R}{J β^{2}}] = 1$

$R = \frac{Joule}{k}$
$\Rightarrow R = \frac{Joule}{k}, k = \frac{Joule}{R}$
$\Rightarrow β = (\frac{Joule}{k})$
$α^{2} β = (\frac{Joule}{k})$
$\Rightarrow α =$ dimensionless

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:Second Law of Thermodynamics

⏱ 2mℹ️ Source: PYQ_2021

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