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Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.Conservative force & potential energyMedium2 minQB

PhysicsMediummultiple choice

The potential energy of a particle of mass 4 kg is given as $U = - 4 x^{2} + 8 x^{4}$ , where x is the position of the particle along positive x -axis from origin. The particle moves along x -axis. Then :

Options:(select one or more)

Answer:

A, B

Solution:

$U^{'} = - 8 x + 32 x^{3} = 0 \Rightarrow x = 0, \frac{1}{2}; U^{''} = - 8 + 96 x^{2}$

At x = 0, $U^{''} < 0$ - PE maximum (A correct). At $x = 1/2$ , $U^{''} > 0$ - PE minimum (B correct). Ans. (A,B)

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Conservative force & potential energy

⏱ 2mℹ️ Source: QB

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