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PhysicsW.E.P.Work kinetic energy theoremMedium2 minPYQ_2020

PhysicsMediumsingle choice

A particle starts with speed $v_{0}$ from $x = 0$ along $x$ -axis with retardation proportional to the square of its displacement. Work done by the force acting on the particle is proportional to

Options:

Answer:

Solution:

Given $a = - {Kx}^{2}$

or $- v \frac{dv}{dx} = x^{2}$

integrating both sides

$- \frac{1}{2} (v^{2} - v_{0}^{2}) = \frac{x^{3}}{3}$

Now, using work-energy theorem $W = ∆ KE$

$W \propto x^{3}$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Work kinetic energy theorem

⏱ 2mℹ️ Source: PYQ_2020

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