A block is released from rest on an fixed incline plane from a height 6 m above the ground as shown in figure where coefficient of friction between block and incline plane is 0.5 . Choose the correct option(s) for motion of block from shown position to the bottom of incline :-

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W mg ​ = mgh = 5 × 10 × 6 = 300 J Δ U = − 300 J W N ​ = 0 (displacement is perpendicular to normal) W f ​ = − μ mgcos θ x = − 0.5 × 5 × 10 × 5 4 ​ × 10 = − 200 J W all ​ = Δ KE

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Options:(select one or more)

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