One mole of an ideal gas requires 207 J of heat to raise its temperature by 10 K when heated at constant pressure. If the same gas is heated at constant volume to raise the temperature by the same 10

Question

One mole of an ideal gas requires 207 J of heat to raise its temperature by 10 K when heated at constant pressure. If the same gas is heated at constant volume to raise the temperature by the same 10 K, the heat required will be ( $R = 8.3$ J $K^{- 1}$ $m o l^{- 1}$ ):

Options:

Answer:

D

Solution:

$C_{p} = 20.7$ J/mol K, $C_{v} = C_{p} - R = 12.4$ . $Q = 12.4 \times 10 = 124$ J. D.

TestHub · Accepted Answer

C p ​ = 20.7 J/mol K, C v ​ = C p ​ − R = 12.4 . Q = 12.4 × 10 = 124 J. D.

Physics - Heat & Thermo Question with Solution | TestHub

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