By the thermal analogy with electricity, the thermal resistance of a rod is R = K A L . Find the thermal resistance in K per W of a copper rod of length 0.5 m and area 2 × 1 0 − 4 m 2 ( K = 400 W m − 1 K − 1 ; two decimals).

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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoHeat TransferMedium2 min

PhysicsMediumnumerical

By the thermal analogy with electricity, the thermal resistance of a rod is $R = \frac{L}{K A}$ . Find the thermal resistance in K per W of a copper rod of length 0.5 m and area $2 \times 1 0^{- 4}$ $m^{2}$ ( $K = 400$ W $m^{- 1}$ $K^{- 1}$ ; two decimals).

Answer:

6.25

Solution:

$R = \frac{L}{K A} = \frac{0.5}{400 \times 2 \times 1 0 ^{- 4}} = 6.25$ K $W^{- 1}$ . Temperature difference plays the role of potential difference and heat current that of electric current.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Heat Transfer

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