Add 20 g ice at 0°C to 100 g water at 40°C. No losses or vessel heat. cw = 1 cal / ( g ∘ C ) , Lf = 80 cal / g . Find final temperature in °C.

Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoThermal ExpansionMedium2 minQB

PhysicsMediuminteger

Add 20 g ice at 0°C to 100 g water at 40°C. No losses or vessel heat. $cw = 1 cal / (g^{\circ} C), Lf = 80 cal / g$ . Find final temperature in °C.

Answer:

Solution:

4000 cal is available cooling water to 0°C, enough to melt ice (1600 cal). Then $100 (40 - T) = 1600 +$ $20 T$ , giving $T = 2 0^{\circ} C$ .

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermal Expansion

⏱ 2mℹ️ Source: QB

Loading discussions...