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PhysicsHeat & ThermoThermodynamics Laws & Specific Heats of GasesMedium2 minQB

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On a graph of $log P$ against $log V$ for an ideal gas, the points lie on a straight line of gradient $- \frac{5}{3}$ . The gas may be:

Answer:

Solution:

$P V^{γ} = constant$ gives $log P = - γ log V + constant$ , so $γ = \frac{5}{3}$ . That is a monoatomic gas in an adiabatic change. A.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermodynamics Laws & Specific Heats of Gases

⏱ 2mℹ️ Source: QB

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