One mole of an ideal monoatomic gas undergoes the process p = p 0 + V α with p 0 = 1 0 5 Pa and α = 50 J. Find the heat capacity of the gas in J K − 1 at V = 0.01 m 3 (two decimals).

C = γ − 1 γ R + p 0 V α R = 2 5 R + 1 0 5 × 0.01 50 R = 2.55 R = 21.20 J K − 1 .

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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoThermodynamics Laws & Specific Heats of GasesHard2 minQB

PhysicsHardnumerical

One mole of an ideal monoatomic gas undergoes the process $p = p_{0} + \frac{α}{V}$ with $p_{0} = 1 0^{5}$ Pa and $α = 50$ J. Find the heat capacity of the gas in J $K^{- 1}$ at $V = 0.01$ $m^{3}$ (two decimals).

Answer:

21.20

Solution:

$C = \frac{γ R}{γ - 1} + \frac{α R}{p _{0} V} = \frac{5}{2} R + \frac{50 R}{1 0 ^{5} \times 0.01} = 2.55 R = 21.20$ J $K^{- 1}$ .

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermodynamics Laws & Specific Heats of Gases

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