A diatomic gas, having C P = 7 2 R and C V = 5 2 R , is heated at constant pressure. The ratio d U : d Q : d W

d U = n C v d T ⇒ d Q = n C p d T ⇒ d W = P d V = n R d T (isobaric process) d U : d Q : d W : C v : C p : R = 5 R 2 : 7 R 2 : R = 5 : 7 : 2 .

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PhysicsHeat & ThermoFirst lawMedium2 minPYQ_2021

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A diatomic gas, having $C_{P} = \frac{7}{2} R$ and $C_{V} = \frac{5}{2} R,$ is heated at constant pressure. The ratio $d U : d Q : d W$

Answer:

Solution:

$d U = n C_{v} d T$ $\Rightarrow d Q = n C_{p} d T$ $\Rightarrow d W = P d V = n R d T$ (isobaric process)

$d U : d Q : d W : C_{v} : C_{p} : R$ $= \frac{5 R}{2} : \frac{7 R}{2} : R = 5 : 7 : 2$ .

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:First law

⏱ 2mℹ️ Source: PYQ_2021

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