An engine working at 60% of its Carnot efficiency between 60 0 ∘ C and 25 0 ∘ C produces 2000 kW of work. Find the heat discharged per hour in units of 1 0 10 J (two decimals).

η C = 1 − 873 523 = 0.4009 , η = 0.6 η C = 0.2405 . Heat input rate = 0.2405 2 × 1 0 6 W, so the discharge rate is 6.31 × 1 0 6 W. Per hour: 2.27 × 1 0 10 J.

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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoThermodynamics Laws & Specific Heats of GasesMedium2 minQB

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An engine working at 60% of its Carnot efficiency between $60 0^{\circ}$ C and $25 0^{\circ}$ C produces 2000 kW of work. Find the heat discharged per hour in units of $1 0^{10}$ J (two decimals).

Answer:

2.27

Solution:

$η_{C} = 1 - \frac{523}{873} = 0.4009$ , $η = 0.6 η_{C} = 0.2405$ . Heat input rate = $\frac{2 \times 1 0 ^{6}}{0.2405}$ W, so the discharge rate is $6.31 \times 1 0^{6}$ W. Per hour: $2.27 \times 1 0^{10}$ J.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermodynamics Laws & Specific Heats of Gases

⏱ 2mℹ️ Source: QB

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