0.5 kg of ice at 0°C is mixed with 0.8 kg of water at 60°C. c w = 4200 J / ( kg K ) , L f = 3.36 × 1 0 5 J / kg . The final state is:

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PhysicsHeat & ThermoThermal ExpansionMedium2 minQB

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0.5 kg of ice at 0°C is mixed with 0.8 kg of water at 60°C. $c_{w} = 4200 J / (kg K), L_{f} = 3.36 \times 1 0^{5} J / kg$ . The final state is:

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Answer:

Solution:

Water can give $0.8 (4200) (60) = 201600 J$ ; melting all ice needs 168000 J. All ice melts and 33600 J remains for $1.3 kg : Δ T = \frac{33600}{1.3 ( 4200 )} = 6.1 5^{\circ} C . B$ .

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermal Expansion

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