Start Free Mock LoginAlready registered? Login here

Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoThermal ExpansionMedium2 minQB

PhysicsMediumnumerical

A hypothetical substance has $c (t) = 0.02 t^{2} cal g^{- 1}^{\circ} C^{- 1}$ , with $t$ the numerical Celsius temperature. Find heat in cal to warm 5 g from $1 0^{\circ} C$ to $2 0^{\circ} C$ . Give one decimal place.

Answer:

233.30

Solution:

$Q = m \int_{10}^{20} c (t) d t$ .

$Q = (5) (0.02) [\frac{t ^{3}}{3}]_{10}^{20} . Q = \frac{700}{3} = 233.333 \dots cal.$

To one decimal place, 233.3 cal.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermal Expansion

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...