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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoHeat TransferEasy2 min

PhysicsEasysingle choice

A slab is made of two parallel layers of equal thickness and width side by side, with conductivities 50 and 150 W $m^{- 1}$ $K^{- 1}$ . Find the equivalent conductivity in W $m^{- 1}$ $K^{- 1}$ .

Options:

Answer:

Solution:

Equal areas in parallel: $k_{e q} = \frac{k _{1} + k _{2}}{2} = \frac{50 + 150}{2} = 100$ . B.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Heat Transfer

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