Physics - Heat & Thermo Question with Solution | TestHub

Work done in cycle$=$area under closed curve

$W=P_0{V}_0$

Heat given$=Q_{AB}+Q_{BC}$

$=n{C}_V \Delta T_{AB}+n{C}_p \Delta T_{BC}$

$=\frac{3}{2}\left(nR{T}_B-nR{T}_A\right)+\frac{5}{2}\left(nR{T}_C-nR{T}_B\right)$

$=\frac{3}{2}\left(2P_0{V}_0-P_0{V}_0\right)+\frac{5}{2}\left(4P_0{V}_0-2P_{0}V\right)$

$=\frac{13}{2} P_0{V}_0$

Thermal efficiency,$\eta =\frac{W}{Q_{absorbed}}=\frac{2}{13}=0.15$