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Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.Calculation of workMedium2 minQB

PhysicsMediumsingle choice

Passage / Comprehension

Comprehension : (3 questions)

In a second ODI match between England and India Bhuwnesh kumar bowled his medium fast bowling. He starts his run up from the distance of 50 m from the stumps (bowling end) and at the time of bowling a ball, his speed is 36 km/hr and the speed of ball is 144 km/hr. If his mass is 70 kg and mass of the ball is $\frac{1}{4}$ kg and the heat produce in his body is one tenth of the total work done by him, then

If he accelerates uniformly to the stumps find the average friction force acting on him :-

Options:

Answer:

Solution:

$(36 \times \frac{5}{18})^{2} = 0^{2} + 2 \times a \times 50 \Rightarrow a = 1 m / s^{2}$

$∴ F = m \times a = (70 + \frac{1}{4}) \times 1 N = 70.25 N$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Calculation of work

⏱ 2mℹ️ Source: QB

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