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Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.MiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

The potential energy for a force field $\vec{F}$ is given by $U (x, y) = \cos (x + y)$ . The force acting on a particle at the position given by coordinates $(0, π / 4)$ is

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Answer:

Solution:

$F_{x} = - \frac{\partial U}{\partial x} = sin (x + y)$ , $F_{y} = - \frac{\partial U}{\partial x} = sin (x + y)$

$F_{x} = {sin (x + y)}_{(0, π / 4)} = \frac{1}{\sqrt{2}}$ ,

$F_{y} = {sin (x + y)}_{(0, π / 4)} = \frac{1}{\sqrt{2}}$

$∴ F = \frac{1}{\sqrt{2}} (\hat{i} + \hat{j})$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:W.E.P.Subtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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