Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoThermodynamicsMedium2 minQB

PhysicsMediumsingle choice

The efficiency of a Carnot engine that operates between the temperatures 400 K and 1200 K is

Answer:

Solution:

$η = 1 - \frac{T _{2}}{T _{1}} = 1 - \frac{400}{1200} = \frac{2}{3} = 0.67$ .

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:Thermodynamics

⏱ 2mℹ️ Source: QB

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