24 J of heat is given to a gas in a cylinder open to the atmosphere ( 1 0 5 Pa), closed by a smooth piston of area 3 × 1 0 − 4 m 2 . The piston moves out by 15 cm. By how much (in joules) does the internal energy of the gas increase?

W = P 0 A d = 1 0 5 × 3 × 1 0 − 4 × 0.15 = 4.5 J. Δ U = Q − W = 24 − 4.5 = 19.5 J.

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PhysicsHeat & ThermoThermodynamics Laws & Specific Heats of GasesEasy2 minQB

PhysicsEasynumerical

$24$ J of heat is given to a gas in a cylinder open to the atmosphere ( $1 0^{5}$ Pa), closed by a smooth piston of area $3 \times 1 0^{- 4}$ $m^{2}$ . The piston moves out by 15 cm. By how much (in joules) does the internal energy of the gas increase?

Answer:

19.50

Solution:

$W = P_{0} A d = 1 0^{5} \times 3 \times 1 0^{- 4} \times 0.15 = 4.5$ J. $Δ U = Q - W = 24 - 4.5 = 19.5$ J.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermodynamics Laws & Specific Heats of Gases

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