Mix 100 g ice at -20°C with 200 g water at 1 0 ∘ C . ci = 0.5 , cw = 1 cal / ( g ∘ C ) , Lf = 80 cal / g . Find remaining ice in g.

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PhysicsHeat & ThermoThermal ExpansionMedium2 minQB

PhysicsMediumnumerical

Mix 100 g ice at -20°C with 200 g water at $1 0^{\circ} C . ci = 0.5, cw = 1 cal / (g^{\circ} C), Lf = 80 cal / g$ . Find remaining ice in g.

Answer:

87.50

Solution:

Water cooling releases 2000 cal; ice warming uses 1000 cal. Remaining 1000 cal melts 12.5 g. Thus ice $= 87.5 g$ ; water $= 212.5 g$ at $0^{\circ} C$ .

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermal Expansion

⏱ 2mℹ️ Source: QB

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