A man swims with same speed relative to river irrespective of whether water is flowing or not. He swims at an angle of $θ$ to bank as shown in 2 figures. Velocity of river flow > Velocity of man in still water.

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Crossing time depends only on the component of the swimmer's velocity perpendicular to the bank:

$t = \frac{d}{v sin θ}$

same in both cases, so (A). Minimum time needs sin theta = 1, i.e. swimming perpendicular to the flow, so (D). Drift is different in the two cases. Answer A, D.

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