Physics - Kinematics Question with Solution | TestHub

PhysicsKinematics1-DHard2 minQB

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Passage / Comprehension

A student tosses a rubber ball vertically upward. When it reaches the top of its trajectory at point A, another student flips the gravity switch so that the acceleration due to gravity now becomes $10 m / s^{2}$ upwards. The ball bounces back to point B, then to the ceiling and sticks there.

Point A is halfway between the floor and ceiling, and point B is $1/4$ ᵗʰ of the way down from the ceiling. Take $y = 0$ at the floor and the positive $y$ -axis upward.

If $h = 40 m$ , then find the total time taken by ball to stick on ceiling after the flip of gravity switch

Options:

Answer:

Solution:

$s = ut + \frac{1}{2}$ at $^{2}$ at point a is velocity is zero, so $t = \frac{2 s}{g}$

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:1-D

⏱ 2mℹ️ Source: QB

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