Physics - Kinematics Question with Solution | TestHub

Let the initial velocity of the body be v. Hence the final velocity = v/2 Applying $v^2=u^2-2as\Rightarrow {\left(\frac{v}{2}\right)}^2=v^2-2\cdot a\cdot 3\Rightarrow a=v^2/8$ In IInd case when the body comes to rest, final velocity = 0, initial velocity = v/2 Again, $(0{)}^2={\left(\frac{v}{2}\right)}^2-2\cdot \frac{v^2}{8}\cdot s;$ or $s=1\mathrm{cm}$ So the extra penetration will be $1\mathrm{cm}$